Reply To: The Riddle Thread….

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#1069669
am yisrael chai
Participant

Icot

This is Buffon’s needle problem that uses integral geometry to approximate pi if the length of the pencil is not greater than the width of the line.

let

L= length of pencil

t= parallel lines are t units apart

x= the distance from the center of the pencil to the closest line

?= the acute angle between the pencil and the lines

The probability density function of x between 0 and t /2 is

(2/t)dx.

The probability density function of ? between 0 and ?/2 is

(2/?)d?.

x and ? are independent random variables, so the joint probability density function is

(4/t?)dxd?.

The pencil crosses the line when

x<=(L/2)sin?.

1. If it’s a short pencil & L<=t:

Integrate the joint probability density function to get the probability that the pencil will cross a line:

= 2L/t?

2. If it’s a longer pencil, the calcualtions r more complicated but solvable