I can only try-
OK I gave it an hour and no one answered.
Change is good: I
I would remove 1 on my first turn.
Each subsequent turn I would pick the amount that when added to the amount he took would equal 7. (If he picked 2 I would pick 5…)
Therefore 1 => 8 => 15 => 22 => 29 => 36 => 43.
There are now seven pennies left.
Any number he chooses to remove now will leave as little as one and as much as six left. I choose the rest and win!