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September 21, 2010 3:51 am at 3:51 am
#1069149
Dr. Pepper
Participant
Take the log (stam log is base 10) of (2^43,112,608)*((2^43,112,609)-1)
Log((2^43,112,608)*((2^43,112,609)-1)) =
Log(2^43,112,608) + Log((2^43,112,609)-1) =
Log(2^43,112,608) + Log(2^43,112,609)=
(For simplicity sake you can remove the -1 since it’s not going to make a difference anyway)
43,112,608 * Log (2) + 43,112,609 * Log (2) =
25,956,376.7
Round up to the nearest integer 25,956,377.