Reply To: The Riddle Thread….

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#1069149
Dr. Pepper
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Take the log (stam log is base 10) of (2^43,112,608)*((2^43,112,609)-1)

Log((2^43,112,608)*((2^43,112,609)-1)) =

Log(2^43,112,608) + Log((2^43,112,609)-1) =

Log(2^43,112,608) + Log(2^43,112,609)=

(For simplicity sake you can remove the -1 since it’s not going to make a difference anyway)

43,112,608 * Log (2) + 43,112,609 * Log (2) =

25,956,376.7

Round up to the nearest integer 25,956,377.