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January 2, 2009 5:45 pm at 5:45 pm
#649429
squeak
Participant
Adar is not the correct answer. Adar II always has 2 days of R”CH, and so does Adar I in a regular year. In a leap year, Adar I always has one day R”CH. So the last Adar always has two days, and the extra one is really the first, which always has one day (that sounds funny, but in the fixed calendar it makes sense – we always know in advance whether there will be one or two, so we give the first one the ‘extra’ status).
Hint: Half of the answer can be found in my response to the mod’s riddle in the riddle thread.