What is the sum of the coefficients of
( [3x – 3x^2 +1]^744 ) x ( [- 3x + 3x^2 +1]^745 ) ?
intellegent, some tips…
There is a rule of exponents;
(a^b) * (a^c) = a^(b+c).
So, since the stuff inside the parenthesis is the same (3x – 3x^2 + 1), this expression can be rewritten as:
(3x – 3x^2 + 1)^(744+745) = (3x – 3x^2 + 1)^1489.
The coefficients are 3 [from the 3x] and -3 [from the -3x^2], and 1 is a constant.