Home › Forums › Yeshiva / School / College / Education Issues › 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ? › Reply To: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?
July 8, 2013 12:41 am at 12:41 am
#1125394
SecularFrummy
Member
x = y.
Then x^2 = xy.
Subtract the same thing from both sides:
x^2 – y^2 = xy – y^2.
Dividing by (x-y), obtain
x + y = y.
Since x = y, we see that
2 y = y.
Thus 2 = 1, since we started with y nonzero.
Subtracting 1 from both sides,
1 = 0.