1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?

Home Forums Yeshiva / School / College / Education Issues 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?

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  • #1125368

    gotbeer
    Member

    Using PEMDAS the answer is 4…..here is how: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 =

    You would first do 1 x 0= and get 0.

    Then you add the 1’s till the minus sign (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) which is equal to 10.

    Then you add what ever is left after the minus sign and get 6 (1 + 1 + 1 + 1 + 1 + 1).

    Then you add the 0 to the 6 and you get 6.

    Then you subtract 10 – 6=4……simple math !!!!!!

    #1125369

    gotbeer
    Member

    BTW, I used a regular calculator and got 14. However, if you would use a scientific calculator, then I believe the answer will be 4.

    #1125370

    haifagirl
    Participant

    gotbeer: It doesn’t work like that. With no parentheses, you don’t subtract 6, you subtract 1. In PEDMAS you do the division and multiplication from left to right, then the addition and subtraction from left to right. You don’t put in parentheses that weren’t in the original problem.

    #1125371

    Now that we’ve had over 50 comments discussing a fifth-grade math question entailing addition, subtraction and multiplication, perhaps we can move up a notch unto division:

    Can we extend this for another 50 responses, debating this highly complex equation?

    #1125372

    yeshivaguy45
    Participant

    48,651

    #1125373

    I’m always amazed at the number of young Einsteins to be found on this board.

    #1125374

    MeemaYehudis
    Member

    Yeshivaguy beat me to it. I agree. 48,651.

    #1125376

    Curiosity
    Participant

    How about

    ? ?(1+4t^2) dt

    ?

    #1125377

    Sam2
    Participant

    Curiosity: Where does a violin fit into a math problem? 😛

    #1125378

    ursketching
    Member

    YitB- i think it’s time to say the answer. everyone is making a fool out of themselves.

    #1125379

    Curiosity
    Participant

    lol Sam2… that’s not a violin! That’s obviously a cello!!!

    It’s actually called an indefinite integral.

    #1125380

    Sam2
    Participant

    Curiosity: Not that it looks like a violin. All violins have the same greek letter to the sides of the strings at the bottom. I have no ideas if cellos do as well.

    #1125381

    Curiosity
    Participant

    They do, and I think they’re called “F-holes”, if I remember correctly. But seriously though, major brownie points to whoever can solve the integral and show their work 🙂

    #1125382

    WIY
    Member

    curiosity

    I am no big mathematician so I googled the problem and was easily able to get the answer which I wont post.

    #1125383

    mattzerino
    Participant

    There is a thing called precedence of operations in algebra. In the lack of any type of parenthesis, the order is division, mult, subtraction and addition. First, you mult. Then all the adding stuff. Should come out to 14, on a good day. Is this an advanced Beis Yaakov arithmetic test, or what?

    #1125384

    Curiosity
    Participant

    Are you sure you didn’t find the answer to

    ? 1/(?(1+4t^2)) dt

    Or

    ? dt/(1+4t^2)

    instead of

    ? ?(1+4t^2) dt

    ? : ) I couldn’t find that particular one on Google, but there are (lengthier) ways of solving it, and programs that calculate anti-derivatives for you.

    #1125385

    OneOfMany
    Participant

    uhhh…something + C?

    #1125386

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 x 0 = ?

    Using PEMDAS, I started with 1 x 0. Automatically, that takes away that 1.

    Then, all I did was just follow the line. Since I took the last 1 away, the problem looks like this:

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 = ?

    I added 14 1’s and subtracted 1 as shown.

    My answer is 13.

    #1125387

    RG3
    Member

    Go bck to school …whoops I mean college oh I forgot u didn’t go

    #1125388

    ☕ DaasYochid ☕
    Participant

    My answer is 13.

    You changed the question, so you got a different answer. The answer to the OP’s question is still 14.

    If the question was “1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 x 0 = ?”, the answer would be 12.

    #1125389

    OneOfMany
    Participant

    Nu, Curiosity – did I get it right? ^_^

    #1125391

    sassy one
    Member

    ? dt/(1+4t^2) = tar[r]^1(t)

    first answer ?(1+4t^(2)+2t)/2

    #1125392

    wastingtime
    Member

    =0 ppl r so bored

    #1125393

    ubiquitin
    Participant

    wastingtime Are you serious?

    If so, wow just wow.

    #1125394

    x = y.

    Then x^2 = xy.

    Subtract the same thing from both sides:

    x^2 – y^2 = xy – y^2.

    Dividing by (x-y), obtain

    x + y = y.

    Since x = y, we see that

    2 y = y.

    Thus 2 = 1, since we started with y nonzero.

    Subtracting 1 from both sides,

    1 = 0.

    #1125395

    TheMusicMan
    Participant

    I believe the correct answer is Swiss cheese.

    Or South Dakota.

    #1125396

    notoriouspre
    Member

    The correct answer is 4. 0x1= 0. Then there are 10 ones on the left of the subtraction sign. And 6 on the right side. Finally 10 minus 6 equals 4. Basic order of operations, and looking closely at the equation. You’re very welcome.

    #1125397

    oomis
    Participant

    Anything that is multiplied by zero, no matter how many digits it has = zero.

    Unless there is a parentheses in there somewhere at the very end, in which case the answer would actually be a real number.

    #1125398

    just my hapence
    Participant

    gotbeer and notoriouspre – BODMAS (or, as you seem to call it in America, PEDMAS) is a list of 4 operations, not 6: 1. Brackets, 2. Other (indices, surds etc), 3. Division AND Multiplication 4. Addition AND Subtraction. When faced with a problem like the one above, do ALL the multiplications and divisions first, from left to right (unless the division is expressed as a fraction in which case deal with the numerator and denominator separately), then ALL of the additions and subtractions from left to right, not all the additions first then all subtractions. So in this case, first do the 1×0 as you said but then you do not add all the 1’s to the left of the subtraction sign and subtract all the 1’s to the right of it from them but rather you add all the 1’s to the left then subtract the 1 immediately to the right of the subtraction sign and then carry on adding all the 1’s.

    #1125399

    just my hapence
    Participant

    oomis – See above. Always do multiplications and divisions BEFORE additions and subtractions. So the only thing being multiplied by 0 here is the very last 1. You can add and subtract all the rest afterwards. Incidentally, 0 is also a real number.

    #1125400

    computer programs give the answer 14

    #1125401

    moishyk
    Member

    i got 14

    #1125402

    moi aussi
    Member

    Zero

    #1125403

    I am ready to cry after having read through this thread.

    #1125404

    oomis
    Participant

    Zero. Anything x 0 is always zero.

    #1125405

    ITS THIRD GRADE MATH!!!!!! HAVE YOU HEARD OF PEMDAS??? THIS IS SO PITIFUL!!

    #1125406

    DikDukDuck
    Participant

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (1 * 0) = 14

    (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1) * 0 = 0

    #1125407

    frumnotyeshivish
    Participant

    PulsingFlower- I see it as ignorance. The concept isn’t difficult. The issue is that many people have never come across the concept in a way that they remember. This shows a lack of schooling (or an awful memory, which perhaps might be pitiful, but it doesn’t seem that you were thinking along those lines), and lack of any real life experiences that require simple math rules. Many people have no need for such knowledge and live complete lives without it. I don’t see inherent value in knowing simple math rules, thus I have no pity for those who were never exposed to them.

    #1125408

    I made the same mistake. my math woes are well documented on this site ( see one of the Lakewood matzav threads where boruch Schwartz absolutely schooled me on some simple math thingy). when I see a math example, my attention gets divided, my misery gets added, and my pleasure gets subtracted. I used to think algorithims are statements attributed to a former vice president and global warming alarmist. its not ignorance, just nerves I get nervous and cant think straight

    #1125409

    I used to think algorithims are statements attributed to a former vice president and global warming alarmist. its not ignorance, just nerves I get nervous and cant think straight

    Actually, that is ignorance.

    #1125410

    actually that was a bad pun

    #1125411

    gefen
    Participant

    I got 16

    #1125412

    ✡onegoal™
    Participant

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (1 x 0) = ?

    1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + (0) = ?

    10 – 6 + 0 = ?

    10 – 6 + 0 = 4

    #1125413

    frumnotyeshivish
    Participant

    Bump… For entertainment purposes. Anything times zero is zero, right?

    #1125414

    ari-free
    Participant

    You are all wrong. The answer to everything is 42!

    #1125415

    ari-free
    Participant

    OK seriously…

    Yes anything times zero is zero. And if you have pq=0 then you know either p is 0 or q is 0 or both.

    Another way to think about multiplication is that you are making combinations. If I had 3 colors and 4 shapes then I have 3×4 = 12 combinations of colored shapes.

    But if I had 5 shapes and no colors I would have zero combinations of ‘colored shapes’ since…there are no colors.

    And that’s the nice thing about multiplication, because you can take say velocity and time, multiply them together, cancel the units and get the distance.

    #1125416

    my own kind of jew
    Participant

    This is hilarious, in a sad sort of way

    #1125417

    oomis
    Participant

    It depends on how you perceive the last two numbers listed. ANYTHING you add or subtract and then multiply by 0, will always be 0. Unless the last two numbers were bracketed together as [1+0], which would actually be 1, the 0 becomes the multiplier, thus ending in a solution of…0 in this problem.

    #1125418

    ari-free
    Participant

    oomis sorry you are wrong. We have to follow the rules. You said

    “ANYTHING you add or subtract and then multiply”

    No we multiply first and then add!

    So 1 + 1 X 0 = 1 because we first evaluated the multiplication of 1 X 0 = 0

    So we have 1 + 0 and that’s 1

    #1125419

    ubiquitin
    Participant

    Oomis, the beauty of math is there is no such thing as “depends how you percieve it” there are strict rules as several posters have explained. following PEMDAS the answer is 14 ANY other response is simply wrong.

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