Reply To: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 – 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 = ?

@ubiquitin the problem with “8÷2(2+2) =” is the inconsistent notation. In general when you use x(y) to multiply, you will use a bar to divide, “8/2(2+2)” which makes it a lot clearer that “2(2+2)” is the denominator and “8” is the numerator.