November 14, 2008 12:15 am at 12:15 am #1067731AnonymousInactive
Speaking from the perspective of this moderator and only this moderator:
this riddle thread is keeping my head spinning like a dreidel…November 14, 2008 12:18 am at 12:18 am #1067732
Moderator: do you enjoy having to read every riddle?November 14, 2008 12:19 am at 12:19 am #1067733
Rashi Pesachim 4a for explanation.November 14, 2008 2:33 am at 2:33 am #1067734dont have internetMember
this is a great topic bec there is no lashon hora and there cant be so much machlokes
and even with that there are still loads and loads of postsNovember 14, 2008 2:55 am at 2:55 am #1067735
Moderator- good to get you thinking a bit!!! 🙂November 14, 2008 4:31 am at 4:31 am #1067736
Here’s one from the textbook I used for calculus;
A hiker takes his time walking slowly and making many stops along a trail from 7:00 A.M. to 7:00 P.M. where he rests for the night. The next morning at 7:00 A.M. he begins his leisurely walk back along the exact same route, again making many stops along the way (not necessarily in the same places), and finishing at 7:00 P.M.
Is there for certain a place along the route where he was in that exact spot the same time on both days? The question isn’t asking where the particular spot is, only if such a particular spot exists.
(Hint: The answer book wanted required a minimal knowledge of function graphing, however this can be answered with no math background.)November 14, 2008 4:55 am at 4:55 am #1067737
First rashi on the amud, let’s not deprive someone else a chance to look it up.
Maybe, but not necessarily.
If he finishes more than an average of 50% of the journey before 50% of the time is up, he won’t ever be in the same place at the same time.November 14, 2008 4:57 am at 4:57 am #1067738
Thisis a puzzle from a book:
Here are six nines-
Can you use them in an equation that totals 100?November 14, 2008 5:11 am at 5:11 am #1067739anon for thisParticipant
Graph his position on the outbound trip, using the x axis for elapsed time for this trip and the y axis for distance from his original starting point. You’ll get a line (or collection of points) that moves from the bottom left to the upper right of the graph. This line will always have a slope greater than or equal to 0, because he’s always either moving forward or resting, never retreating.
Now graph his position for the return trip on the same graph. The line representing this trip will start at the upper left, at the same point along the y axis that the . first line ended, and move to the bottom right. Now this line must always have a negative or zero slope, depending on whether he’s walking or resting.
The two lines must intersect once (and only once). Since the x axis represents elapsed time since that day’s starting point and he started at the same time both days, this means that he reached this particular point at the same time both days.
Even though this problem is intended to be solved through graphing, which is what I do above, it’s easier to imagine two people starting at the same time from opposite points and traveling in a straight line towards each other, stopping occasionally but not moving backwards. It’s intuitively obvious that the two will meet at one particular point.November 14, 2008 5:12 am at 5:12 am #1067740
I take it back…
Yes, they must be at the same place and the same time at one point, just like two cars going in opposite directions on the highway that depart and arrive at the same times.November 14, 2008 5:41 am at 5:41 am #1067741
I did indeed mean day 28, at which point he will be 27 feet high, and only needs to climb another 3 feet, at which point he has reached the top. This is like the riddle,” If you have three pills and they have to be taken at the rate of one every half hour, how much time will pass by the time you have swallowed all three?”November 14, 2008 7:18 am at 7:18 am #1067742David Bar-MagenMember
Q: What can travel all around the world while still staying in one corner?
A: A postage stamp.November 14, 2008 11:57 am at 11:57 am #1067743jewishfeminist02Member
I think Reuven and Chaim might feel out of place at a U2 concert…if you had left the names as Adam and Larry, then it might work 🙂
I don’t have access to a Gemara right now, so I can’t look up the Rashi on Pesachim, but here’s my guess. The man’s parents each had children from previous marriages who later married each other. Thus, the couple are each his (half) siblings but they are halachically allowed to marry since they aren’t blood related to each other.November 14, 2008 1:04 pm at 1:04 pm #1067744
Not really a riddle but interesting anyway- what’s the shortest Daf in Shas?November 14, 2008 1:44 pm at 1:44 pm #1067745
noitallmr, do you mean in terms of the text of the Gemara only, not counting Rashi and Tosafos? If so, it’s in Nazir – daf lamed gimmel, I think, although I’m not sure exactly. One amud has something like 4 lines, the other amud is entirely Tosafos.November 14, 2008 2:01 pm at 2:01 pm #1067746
“I think Reuven and Chaim might feel out of place at a U2 concert”
-Since this is a riddle/puzzle thread, lets treat this as a puzzle and try to figure out the circumstances:
1) How can Reuven and Chaim attend the concert? Besides the music itself, can’t there be a problem of “kol isha” with an opening act? (I think U2 itself is all men)
2) Why did they leave themselves so little time to get there?
3) Why is it so important that they get there on time that they are crossing a dark, unsafe bridge to do so?
The answer is clearly as follows:
Reuven and Chaim are electricians, hired to ensure that the sound system and lighting are up to par and safe thruoughout the concert.
They carefully checked beforehand to ensure there were no woman singers or performers before the concert.
They received a heter iska to be present in the building while the concert was being held.
The concert was scheduled to begin motzei Shabbos, shortly after havdala, which is why they were under such time constraints.
Gut Shabbos.November 14, 2008 2:49 pm at 2:49 pm #1067747
Yes, Reb anon for this, that is correct.November 14, 2008 5:44 pm at 5:44 pm #1067748
Math? Yuck. We managed to avoid those riddles up ’till now. I guess I have a good one, too, then. This was an actual SAT question that no one was able to answer, from back when the T stood for test (oy, I hate making myself look old).
If a person drives to a place at 40 MPH, and then drives back at 30 MPH, and the total trip takes 1 hour with no stops, what is the average speed for the trip? [Note that the distance is the same both ways, and the speed in each direction is not an average but an exact and constant speed].
I think that the 9’s is the only one left outstanding – but it is not specified what order of operation to use.November 14, 2008 6:35 pm at 6:35 pm #1067749
The man who invented it doesn’t want it. The man who bought it doesn’t need it. The man who needs it doesn’t know it. What is it?November 14, 2008 6:37 pm at 6:37 pm #1067750
What can run but never walks, has a mouth but never talks, has a head but never weeps, has a bed but never sleeps?November 14, 2008 9:01 pm at 9:01 pm #1067751
-I’m with you there.
In school I enjoyed history, english and science, but math? not my slice of pi.
Rest assured the “Nines” puzzle does not use any complex equations.
Heres a great, big hint-
The first three characters of the equation are “99+”
I think the answer to your puzzle is about 34.3 MPH.
The logic I used is:
Since he traveled the same distance at the two different speeds, we calculate 2/3 * x = .5 * y with x+y = 60. The closest I can come is about x=25.7, y=34.3 (time) and 17.13 (distance). 2*17.13 is about 34.3
(I may not know what I’m talking about – math majors, please help).
The answer to your second is “a river”November 15, 2008 11:09 pm at 11:09 pm #1067752
Yes the second answer is a river, heres another:
A chest without hinges key or lid but inside golden treasures are hid. What is the chest and what is the treasure?November 15, 2008 11:17 pm at 11:17 pm #1067753
This ones a little bit harder but…
A notorious robber has made a lucrative living by robbing travelers in the forest. Inspector Bob has, after extensive examination of the available clues, identified three suspects. Their statements follow. One makes two true statements; one makes one true and one false statement; one makes two false statements.
A. 1)I am not the robber 2)C is the robber
B. 1)C is innocent 2)A is the robber
C. 1)I am not the robber 2) B is innocent
Which one is the robber?November 15, 2008 11:32 pm at 11:32 pm #1067754
I thought tha was an old one.November 16, 2008 12:19 am at 12:19 am #1067755
“The man who invented it doesn’t want it. The man who bought it doesn’t need it. The man who needs it doesn’t know it. What is it? “
A burial casket?
“What can run but never walks, has a mouth but never talks, has a head but never weeps, has a bed but never sleeps? ”
A river.November 16, 2008 1:50 am at 1:50 am #1067756
The robber one:
a: true, true
b: false, false
c: false, true
gut vochNovember 16, 2008 1:52 am at 1:52 am #1067757
(I am not the author of any of the puzzles I posted, and for the most part don’t know if they’re oldies).November 16, 2008 1:54 am at 1:54 am #1067758
The shortest Daf (Gemara Text) is Bava Kama 77a. Check it out- two lines…November 16, 2008 2:32 am at 2:32 am #1067759
Here’s one for the kids:
What has pains but doesn’t ache
is very hard but easy to break?November 16, 2008 2:34 am at 2:34 am #1067760
“What is the chest and what is the treasure?”
An egg? (the shell and yolk)
A person? (heart of gold)November 16, 2008 5:29 am at 5:29 am #1067761
zimby, you’ve been reading your Tolkien, haven’t you? That is where you got the egg riddle from, right?November 16, 2008 5:46 am at 5:46 am #1067762
ICOT: Right with both, ok for you I have a harder one coming soon.
Oomiss1105: RightNovember 16, 2008 8:59 pm at 8:59 pm #1067763
You take a cigarette out of the box. You don’t have a lighter, flint stones, matches, candle, anyone else near you and no lit cigarettes either. How do you light it?November 16, 2008 10:08 pm at 10:08 pm #1067764
61,52,63,?November 16, 2008 10:10 pm at 10:10 pm #1067765
Do you know me?
I am a man. If Yankel’s son is my son’s father, what relationship am I to Yankel?November 16, 2008 10:12 pm at 10:12 pm #1067766
The earth takes exactly 24 hours to complete one full roatation, right?
Explain your answer.November 16, 2008 10:22 pm at 10:22 pm #1067767
1) Use a magnifying lens and sunlight.
2) Wait until you get a lighter.
3) Call a shadchan, tell him you’re single, and get a match.
4) Join a YW thread and wait for an incendiary comment.November 16, 2008 11:55 pm at 11:55 pm #1067768
1)How do you light it? You don’t. THAT STUFF CAN KILL YOU, MAN!!!!!
(or if desperate, you go to the stove).
2) “I am a man. If Yankel’s son is my son’s father, what relationship am I to Yankel? ‘
I am Yankle’s son.November 17, 2008 12:31 am at 12:31 am #1067769
54??? Probably isn’t coz that’s too easy.
Do you know me?
I am a man. If Yankel’s son is my son’s father, what relationship am I to Yankel?
My son’s father is me so Yankel is my father.
Come on ICOT…you can do better then that! 🙂November 17, 2008 1:17 am at 1:17 am #1067770
re: Who am I? – both correct!
-54??? no, keep on trying.
“Come on ICOT…you can do better then that! :-)”
– ‘fraid not :-pNovember 17, 2008 1:54 am at 1:54 am #1067771
What’s next? (new and improved! with clue enclosed!)
61,52,63,?,46November 17, 2008 9:32 am at 9:32 am #1067772
1) Use a magnifying lens and sunlight. – you don’t have a magnifying glass and its a cloudy day.
2) Wait until you get a lighter. – i want it NOW…
3) Call a shadchan, tell him you’re single, and get a match.- You can light a cigarette with a girl???
4) Join a YW thread and wait for an incendiary comment. – 🙂
Keep trying guys…November 17, 2008 3:29 pm at 3:29 pm #1067773
I think the pattern starts earlier, 1,4,9,61,52,63,94,46,18,001,121,441,961,691,522…
I really enjoyed that one.November 17, 2008 3:34 pm at 3:34 pm #1067774
What’s black and white and red/read/redt all over?November 17, 2008 4:14 pm at 4:14 pm #1067775
squeak, that has more answers than almost any other riddle I know.
A skunk in a blender
A yeshiva bachur on his first date
there are more, I just don’t feel like writing them all.November 17, 2008 8:41 pm at 8:41 pm #1067776
Imagine a digital clock (I wouldn’t stigmatize anyone by saying a digital watch. When the minutes are the same as the hour, that is called a “double”, e.g. 2:02 is a double, as is 10:10.
What is the longest amount of time between doubles? What is the shortest?November 17, 2008 8:51 pm at 8:51 pm #1067777
Eisav and Yishmael are fighting. The UN decided to stop the fighting (for a change) and took a piece of paper, drew a line down the middle and ordered them to each stand on one half of the paper. Though they were both on the same piece of paper, and within 11 inches of each other, neither one was able to hit or even touch the other. How is that possible?November 17, 2008 9:24 pm at 9:24 pm #1067778havesomeseichelMember
Ok, about this watch/clock…
all the numbers from 1:01 to 9:09 are 61 minutes in between doubles.
9:09 to 10:10 is 61
10:10-11:11 is also 61 minutes
but the shortest one is, if on army time: 11:11-0:00 only 49 minutes!
and 12:12-101 is the shortest one if not on army time! Also 49 minutes!
The longest one…. hmmmNovember 17, 2008 9:25 pm at 9:25 pm #1067779dont have internetMember
can i make a suggestion? that when u are answering or giving an answer say which 1 u are answering like 2nd page 4th from top—or at least say the question—thanxNovember 17, 2008 10:07 pm at 10:07 pm #1067780feivelParticipant
Eisav and Yishmael are fighting. The UN decided to stop the fighting (for a change) and took a piece of paper, drew a line down the middle and ordered them to each stand on one half of the paper. Though they were both on the same piece of paper, and within 11 inches of each other, neither one was able to hit or even touch the other. How is that possible?
they were in separate rooms
the paper was placed under the door and the door closed
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